Hcf of 405 and 2520

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WebApr 9, 2024 · Solution For bond of 32 members in Find the maximum (NCERT) Mathematics-10 arch is & ons to stack them in the least area of the purpose (NCERT In text) of barfis in each he number of Fof 420 and each WebApr 9, 2024 · Solution For y band of 32 sumns Find t nd 32 amarch is 8. wants to stack up the least are this purpose fis of each kin Exercise 1.1 Type Very Short Anower Type Questione 1. Fad the largest number that

bond of 32 members in Find the maximum (NCERT) Mathematics …

WebThere are 6 common factors of 405 and 2520, that are 1, 3, 5, 9, 45, and 15. Therefore, the highest common factor of 405 and 2520 is 45. Therefore, the highest common factor of … WebHCF of 408 and 1032 is the divisor that we get when the remainder becomes 0 after doing long division repeatedly. Step 1: Divide 1032 (larger number) by 408 (smaller number). Step 2: Since the remainder ≠ 0, we will divide the divisor of step 1 (408) by the remainder (216). Step 3: Repeat this process until the remainder = 0. unh oxford

Using Euclid

WebJul 18, 2016 · 2520 = 405 × 6 + 90 Since the remainder 90 , we apply the division lemma to 405 and 90 405 = 90 × 4 + 45 90 = 45 × 2 + 0 The remainder has now become zero, so … WebUsing Euclid's Division Algorithm, Find HCF of 405 & 2520, 504 & 1188 and 960 & 1575 Q4 E1AUsing Euclid's Division Algorithm, Find HCF of:1. 405 & 25202. 5... Web405)2520(6 – 2430 _____ 90)405(4 – 360 _____ 45)90(2 – 90 _____ 0. Apply Euclid’s algorithm, [ Dividing 2520 by 405] Quotient = 6. Remainder = 90. ∴ 2520 = 405 × 6 + 90. … unh ot

Hcf of 405 and 2520 Homework Help myCBSEguide

WebWe know that HCFxLCM = Product of two numbersGiven HCF=40 and LCM=252×kThen 40×252×k=2520×6600On solving this equation we get k=1650So correct answer will be option A. WebApr 28, 2024 · Using Euclid's division algorithm, find the HCF of (i) 405 and 2520 (ii) 504 and 1188 (iii) 960 and 1575. See answers Advertisement LovelyG Answer: (i) 405 and … unh passwordWeb∴ 2520 = 405 × 6 + 90 Again on applying Euclid’s algorithm, i.e. dividing 405 by 90, we get: Quotient = 4, Remainder = 45 ∴ 405 = 90 × 4 + 45 Again on applying Euclid’s algorithm, … unh outlook email

"WebUsing Euclid’s division algorithm, find the HCF of 405 and 2520 Solution On applying Euclid’s algorithm, i.e. dividing 2520 by 405, we get: Quotient = 6, Remainder = 90 … " - Hcf of 405 and 2520

Hcf of 405 and 2520

WebAug 27, 2024 · ∴ 2520 = 405 × 6 + 90 . Again on applying Euclid’s algorithm, i.e. dividing 405 by 90, we get: Quotient = 4, Remainder = 45 ∴ 405 = 90 × 4 + 45 . Again on applying … WebOn dividing 2520 by 405 , we get quotient = 6 , remainder = 90 ... Using Euclid's division algorithm, find the HCF of 4 4 0 7, 2 9 3 8 and 1 4 6 9. Medium. View solution > Using Euclid's division algorithm, find the HCF of 1 3 5 and 2 2 5. Medium. View solution >

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WebUsing Euclid's algortihm, find the HCF of (i) 405 and 2520 (ii) 504 and 1188 (iii) 960 and 1575. Q. Find the HCF of 1260 and 7344 using Euclid's algorithm? Q. Using Euclid's division algorithm find the HCF: 48250, 38540. Q. Using Euclid's algorithm, find the HCF of 405 and 2520. View More. Related Videos. Algebraic Identities. Web405)2520(6 – 2430 _____ 90)405(4 – 360 _____ 45)90(2 – 90 _____ 0. Apply Euclid’s algorithm, [ Dividing 2520 by 405] Quotient = 6. Remainder = 90. ∴ 2520 = 405 × 6 + 90. Apply Euclid’s algorithm, [ Dividing 405 by 90] Quotient = 4. Remainder = 45. ∴ 405 = 90 × 4 + 45. Apply Euclid’s algorithm, [Dividing 90 by 45] ∴ 90 = 45 ...

WebJan 22, 2024 · Therefore, the HCF of 396, 504, 636 is 12. ← Prev Question Next Question →. Find MCQs & Mock Test ... Using Euclid’s algorithm, find the HCF of (i) 405 and 2520 (ii) 504 and 1188 (iii) 960 and 1575. asked Jun 15, 2024 in Number System by Hailley (33.5k points) real numbers; class-10; 0 votes. 1 answer. WebUsing Euclid’s division algorithm, find the HCF of 240 and 228. asked Nov 25, 2024 in Mathematics by Golu (106k points) real numbers; 0 votes. 1 answer. ... Using Euclid’s algorithm, find the HCF of (i) 405 and 2520 (ii) 504 and 1188 (iii) 960 and 1575. asked Jun 15, 2024 in Number System by Hailley (33.5k points) real numbers; class-10; 0 ...

Web$\therefore 2520=405 \times 6+90$ Again upon applying Euclid’s algorithm, that is dividing $405$ by $90$, we obtain Quotient $=4$, Remait $\therefore 405=90 \times 4+45$ Again applying Euclid’s algorithm, that is dividing $90$ by $45$ , we obtain; $\therefore 90=45 \times 2+0$ As a result, the HCF of 2520 and 405 is 45 . WebUsing Euclid’s division algorithm, find the HCF of (i) 405 and 2520 (ii) 504 and 1188 (iii) 960 and 1575. Please scroll down to see the correct answer and solution guide. Right Answer is: SOLUTION (i) On applying Euclid’s algorithm, i.e. …

WebHCF of 25 and 40 is the divisor that we get when the remainder becomes 0 after doing long division repeatedly. Step 1: Divide 40 (larger number) by 25 (smaller number). Step 2: …

WebHCF calculator is a multiservice tool that finds the highest common factor and lowest common factor of the given numbers at the same time. It only needs one input value to … unh oxford loginWebWhen applying Euclid’s algorithm, that is dividing $2520$ by $405$, we obtain, Quotient $=6$, Remainder $=90$ $\therefore 2520=405 \times 6+90$ Again upon applying … unh owlWebSolutions for RS Aggarwal Mathematics Class 10. Show that there is no value of n for which (2n×5n) ends in 5. Find the largest number which when divided by 20, 25, 35 and 40 leaves remainder as 14, 19 ,29 and 34 respectively. Find the greatest number of four digits which is exactly divisible by 15, 24 and 36. Find the smallest number that ... unh paid research